-4(3y-3)-y=-4(y-2)

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Solution for -4(3y-3)-y=-4(y-2) equation: 



-4(3y-3)-y=-4(y-2)

We move all terms to the left:

-4(3y-3)-y-(-4(y-2))=0

We add all the numbers together, and all the variables

-1y-4(3y-3)-(-4(y-2))=0

We multiply parentheses

-1y-12y-(-4(y-2))+12=0



We calculate terms in parentheses: -(-4(y-2)), so:

-4(y-2)

We multiply parentheses

-4y+8

Back to the equation:

-(-4y+8)



We add all the numbers together, and all the variables

-13y-(-4y+8)+12=0

We get rid of parentheses

-13y+4y-8+12=0

We add all the numbers together, and all the variables

-9y+4=0

We move all terms containing y to the left, all other terms to the right

-9y=-4

y=-4/-9

y=4/9

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