-4(3y-4)+12y=

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Solution for -4(3y-4)+12y= equation: 


Simplifying
-4(3y + -4) + 12y = 0

Reorder the terms:
-4(-4 + 3y) + 12y = 0
(-4 * -4 + 3y * -4) + 12y = 0
(16 + -12y) + 12y = 0

Combine like terms: -12y + 12y = 0
16 + 0 = 0
16 = 0

Solving
16 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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