-4(3y-5)+2(2y+10)=

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Solution for -4(3y-5)+2(2y+10)= equation:


Simplifying
-4(3y + -5) + 2(2y + 10) = 0

Reorder the terms:
-4(-5 + 3y) + 2(2y + 10) = 0
(-5 * -4 + 3y * -4) + 2(2y + 10) = 0
(20 + -12y) + 2(2y + 10) = 0

Reorder the terms:
20 + -12y + 2(10 + 2y) = 0
20 + -12y + (10 * 2 + 2y * 2) = 0
20 + -12y + (20 + 4y) = 0

Reorder the terms:
20 + 20 + -12y + 4y = 0

Combine like terms: 20 + 20 = 40
40 + -12y + 4y = 0

Combine like terms: -12y + 4y = -8y
40 + -8y = 0

Solving
40 + -8y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-40' to each side of the equation.
40 + -40 + -8y = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -8y = 0 + -40
-8y = 0 + -40

Combine like terms: 0 + -40 = -40
-8y = -40

Divide each side by '-8'.
y = 5

Simplifying
y = 5

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