-4(3y-6)+2y=2(y+8)

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Solution for -4(3y-6)+2y=2(y+8) equation: 



-4(3y-6)+2y=2(y+8)

We move all terms to the left:

-4(3y-6)+2y-(2(y+8))=0

We add all the numbers together, and all the variables

2y-4(3y-6)-(2(y+8))=0

We multiply parentheses

2y-12y-(2(y+8))+24=0



We calculate terms in parentheses: -(2(y+8)), so:

2(y+8)

We multiply parentheses

2y+16

Back to the equation:

-(2y+16)



We add all the numbers together, and all the variables

-10y-(2y+16)+24=0

We get rid of parentheses

-10y-2y-16+24=0

We add all the numbers together, and all the variables

-12y+8=0

We move all terms containing y to the left, all other terms to the right

-12y=-8

y=-8/-12

y=2/3

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