-4(3y-7)-y=-3(y-4)

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Solution for -4(3y-7)-y=-3(y-4) equation: 



-4(3y-7)-y=-3(y-4)

We move all terms to the left:

-4(3y-7)-y-(-3(y-4))=0

We add all the numbers together, and all the variables

-1y-4(3y-7)-(-3(y-4))=0

We multiply parentheses

-1y-12y-(-3(y-4))+28=0



We calculate terms in parentheses: -(-3(y-4)), so:

-3(y-4)

We multiply parentheses

-3y+12

Back to the equation:

-(-3y+12)



We add all the numbers together, and all the variables

-13y-(-3y+12)+28=0

We get rid of parentheses

-13y+3y-12+28=0

We add all the numbers together, and all the variables

-10y+16=0

We move all terms containing y to the left, all other terms to the right

-10y=-16

y=-16/-10

y=1+3/5

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