-4(3z-8)=-29+7z

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Solution for -4(3z-8)=-29+7z equation: 



-4(3z-8)=-29+7z

We move all terms to the left:

-4(3z-8)-(-29+7z)=0

We add all the numbers together, and all the variables

-4(3z-8)-(7z-29)=0

We multiply parentheses

-12z-(7z-29)+32=0

We get rid of parentheses

-12z-7z+29+32=0

We add all the numbers together, and all the variables

-19z+61=0

We move all terms containing z to the left, all other terms to the right

-19z=-61

z=-61/-19

z=3+4/19

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