-4(4+1)+6u=2(u+2)-8

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Solution for -4(4+1)+6u=2(u+2)-8 equation: 



-4(4+1)+6u=2(u+2)-8

We move all terms to the left:

-4(4+1)+6u-(2(u+2)-8)=0

We add all the numbers together, and all the variables

6u-(2(u+2)-8)-45=0



We calculate terms in parentheses: -(2(u+2)-8), so:

2(u+2)-8

We multiply parentheses

2u+4-8

We add all the numbers together, and all the variables

2u-4

Back to the equation:

-(2u-4)



We get rid of parentheses

6u-2u+4-45=0

We add all the numbers together, and all the variables

4u-41=0

We move all terms containing u to the left, all other terms to the right

4u=41

u=41/4

u=10+1/4

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