-4(4+2z)+12z=44

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Solution for -4(4+2z)+12z=44 equation: 



-4(4+2z)+12z=44

We move all terms to the left:

-4(4+2z)+12z-(44)=0

We add all the numbers together, and all the variables

-4(2z+4)+12z-44=0

We add all the numbers together, and all the variables

12z-4(2z+4)-44=0

We multiply parentheses

12z-8z-16-44=0

We add all the numbers together, and all the variables

4z-60=0

We move all terms containing z to the left, all other terms to the right

4z=60

z=60/4

z=15

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