-4(4-2b)=2(4-2b)

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Solution for -4(4-2b)=2(4-2b) equation: 



-4(4-2b)=2(4-2b)

We move all terms to the left:

-4(4-2b)-(2(4-2b))=0

We add all the numbers together, and all the variables

-4(-2b+4)-(2(-2b+4))=0

We multiply parentheses

8b-(2(-2b+4))-16=0



We calculate terms in parentheses: -(2(-2b+4)), so:

2(-2b+4)

We multiply parentheses

-4b+8

Back to the equation:

-(-4b+8)



We get rid of parentheses

8b+4b-8-16=0

We add all the numbers together, and all the variables

12b-24=0

We move all terms containing b to the left, all other terms to the right

12b=24

b=24/12

b=2

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