-4(4b-8)+2(1+6b)=-8b-1+b-7

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Solution for -4(4b-8)+2(1+6b)=-8b-1+b-7 equation: 



-4(4b-8)+2(1+6b)=-8b-1+b-7

We move all terms to the left:

-4(4b-8)+2(1+6b)-(-8b-1+b-7)=0

We add all the numbers together, and all the variables

-4(4b-8)+2(6b+1)-(-7b-8)=0

We multiply parentheses

-16b+12b-(-7b-8)+32+2=0

We get rid of parentheses

-16b+12b+7b+8+32+2=0

We add all the numbers together, and all the variables

3b+42=0

We move all terms containing b to the left, all other terms to the right

3b=-42

b=-42/3

b=-14

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