-4(4u+4)=3(u+4)+7

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Solution for -4(4u+4)=3(u+4)+7 equation: 



-4(4u+4)=3(u+4)+7

We move all terms to the left:

-4(4u+4)-(3(u+4)+7)=0

We multiply parentheses

-16u-(3(u+4)+7)-16=0



We calculate terms in parentheses: -(3(u+4)+7), so:

3(u+4)+7

We multiply parentheses

3u+12+7

We add all the numbers together, and all the variables

3u+19

Back to the equation:

-(3u+19)



We get rid of parentheses

-16u-3u-19-16=0

We add all the numbers together, and all the variables

-19u-35=0

We move all terms containing u to the left, all other terms to the right

-19u=35

u=35/-19

u=-1+16/19

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