-4(4u-1)+7u=1+3(2u-3)

Solution for -4(4u-1)+7u=1+3(2u-3) equation:

-4(4u-1)+7u=1+3(2u-3)

We move all terms to the left:

-4(4u-1)+7u-(1+3(2u-3))=0

We add all the numbers together, and all the variables

7u-4(4u-1)-(1+3(2u-3))=0

We multiply parentheses

7u-16u-(1+3(2u-3))+4=0


We calculate terms in parentheses: -(1+3(2u-3)), so:

1+3(2u-3)

determiningTheFunctionDomain
3(2u-3)+1

We multiply parentheses

6u-9+1

We add all the numbers together, and all the variables

6u-8

Back to the equation:

-(6u-8)


We add all the numbers together, and all the variables

-9u-(6u-8)+4=0

We get rid of parentheses

-9u-6u+8+4=0

We add all the numbers together, and all the variables

-15u+12=0

We move all terms containing u to the left, all other terms to the right

-15u=-12

u=-12/-15

u=4/5