-4(4u-3)+8u=2+2(5u-1)

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Solution for -4(4u-3)+8u=2+2(5u-1) equation: 



-4(4u-3)+8u=2+2(5u-1)

We move all terms to the left:

-4(4u-3)+8u-(2+2(5u-1))=0

We add all the numbers together, and all the variables

8u-4(4u-3)-(2+2(5u-1))=0

We multiply parentheses

8u-16u-(2+2(5u-1))+12=0



We calculate terms in parentheses: -(2+2(5u-1)), so:

2+2(5u-1)

determiningTheFunctionDomain
2(5u-1)+2

We multiply parentheses

10u-2+2

We add all the numbers together, and all the variables

10u

Back to the equation:

-(10u)



We add all the numbers together, and all the variables

-18u+12=0

We move all terms containing u to the left, all other terms to the right

-18u=-12

u=-12/-18

u=2/3

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