-4(4u-3)+9u=3(u+6)

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Solution for -4(4u-3)+9u=3(u+6) equation: 



-4(4u-3)+9u=3(u+6)

We move all terms to the left:

-4(4u-3)+9u-(3(u+6))=0

We add all the numbers together, and all the variables

9u-4(4u-3)-(3(u+6))=0

We multiply parentheses

9u-16u-(3(u+6))+12=0



We calculate terms in parentheses: -(3(u+6)), so:

3(u+6)

We multiply parentheses

3u+18

Back to the equation:

-(3u+18)



We add all the numbers together, and all the variables

-7u-(3u+18)+12=0

We get rid of parentheses

-7u-3u-18+12=0

We add all the numbers together, and all the variables

-10u-6=0

We move all terms containing u to the left, all other terms to the right

-10u=6

u=6/-10

u=-3/5

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