-4(4v-1)+2v=2(v+8)

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Solution for -4(4v-1)+2v=2(v+8) equation: 



-4(4v-1)+2v=2(v+8)

We move all terms to the left:

-4(4v-1)+2v-(2(v+8))=0

We add all the numbers together, and all the variables

2v-4(4v-1)-(2(v+8))=0

We multiply parentheses

2v-16v-(2(v+8))+4=0



We calculate terms in parentheses: -(2(v+8)), so:

2(v+8)

We multiply parentheses

2v+16

Back to the equation:

-(2v+16)



We add all the numbers together, and all the variables

-14v-(2v+16)+4=0

We get rid of parentheses

-14v-2v-16+4=0

We add all the numbers together, and all the variables

-16v-12=0

We move all terms containing v to the left, all other terms to the right

-16v=12

v=12/-16

v=-3/4

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