-4(4v-3)+8v=6(v+1)

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Solution for -4(4v-3)+8v=6(v+1) equation: 



-4(4v-3)+8v=6(v+1)

We move all terms to the left:

-4(4v-3)+8v-(6(v+1))=0

We add all the numbers together, and all the variables

8v-4(4v-3)-(6(v+1))=0

We multiply parentheses

8v-16v-(6(v+1))+12=0



We calculate terms in parentheses: -(6(v+1)), so:

6(v+1)

We multiply parentheses

6v+6

Back to the equation:

-(6v+6)



We add all the numbers together, and all the variables

-8v-(6v+6)+12=0

We get rid of parentheses

-8v-6v-6+12=0

We add all the numbers together, and all the variables

-14v+6=0

We move all terms containing v to the left, all other terms to the right

-14v=-6

v=-6/-14

v=3/7

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