-4(4v-5)+6v=8+4(2v-1)

Solution for -4(4v-5)+6v=8+4(2v-1) equation:

-4(4v-5)+6v=8+4(2v-1)

We move all terms to the left:

-4(4v-5)+6v-(8+4(2v-1))=0

We add all the numbers together, and all the variables

6v-4(4v-5)-(8+4(2v-1))=0

We multiply parentheses

6v-16v-(8+4(2v-1))+20=0


We calculate terms in parentheses: -(8+4(2v-1)), so:

8+4(2v-1)

determiningTheFunctionDomain
4(2v-1)+8

We multiply parentheses

8v-4+8

We add all the numbers together, and all the variables

8v+4

Back to the equation:

-(8v+4)


We add all the numbers together, and all the variables

-10v-(8v+4)+20=0

We get rid of parentheses

-10v-8v-4+20=0

We add all the numbers together, and all the variables

-18v+16=0

We move all terms containing v to the left, all other terms to the right

-18v=-16

v=-16/-18

v=8/9