-4(4x-3)=-16x+12

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Solution for -4(4x-3)=-16x+12 equation: 



-4(4x-3)=-16x+12

We move all terms to the left:

-4(4x-3)-(-16x+12)=0

We multiply parentheses

-16x-(-16x+12)+12=0

We get rid of parentheses

-16x+16x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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