-4(4y-1)+8y=7+2(2y-6)

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Solution for -4(4y-1)+8y=7+2(2y-6) equation: 



-4(4y-1)+8y=7+2(2y-6)

We move all terms to the left:

-4(4y-1)+8y-(7+2(2y-6))=0

We add all the numbers together, and all the variables

8y-4(4y-1)-(7+2(2y-6))=0

We multiply parentheses

8y-16y-(7+2(2y-6))+4=0



We calculate terms in parentheses: -(7+2(2y-6)), so:

7+2(2y-6)

determiningTheFunctionDomain
2(2y-6)+7

We multiply parentheses

4y-12+7

We add all the numbers together, and all the variables

4y-5

Back to the equation:

-(4y-5)



We add all the numbers together, and all the variables

-8y-(4y-5)+4=0

We get rid of parentheses

-8y-4y+5+4=0

We add all the numbers together, and all the variables

-12y+9=0

We move all terms containing y to the left, all other terms to the right

-12y=-9

y=-9/-12

y=3/4

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