-4(4y-2)+y=3(y+8)

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Solution for -4(4y-2)+y=3(y+8) equation: 



-4(4y-2)+y=3(y+8)

We move all terms to the left:

-4(4y-2)+y-(3(y+8))=0

We add all the numbers together, and all the variables

y-4(4y-2)-(3(y+8))=0

We multiply parentheses

y-16y-(3(y+8))+8=0



We calculate terms in parentheses: -(3(y+8)), so:

3(y+8)

We multiply parentheses

3y+24

Back to the equation:

-(3y+24)



We add all the numbers together, and all the variables

-15y-(3y+24)+8=0

We get rid of parentheses

-15y-3y-24+8=0

We add all the numbers together, and all the variables

-18y-16=0

We move all terms containing y to the left, all other terms to the right

-18y=16

y=16/-18

y=-8/9

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