-4(4y-2)-y=-3(y-5)

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Solution for -4(4y-2)-y=-3(y-5) equation: 



-4(4y-2)-y=-3(y-5)

We move all terms to the left:

-4(4y-2)-y-(-3(y-5))=0

We add all the numbers together, and all the variables

-1y-4(4y-2)-(-3(y-5))=0

We multiply parentheses

-1y-16y-(-3(y-5))+8=0



We calculate terms in parentheses: -(-3(y-5)), so:

-3(y-5)

We multiply parentheses

-3y+15

Back to the equation:

-(-3y+15)



We add all the numbers together, and all the variables

-17y-(-3y+15)+8=0

We get rid of parentheses

-17y+3y-15+8=0

We add all the numbers together, and all the variables

-14y-7=0

We move all terms containing y to the left, all other terms to the right

-14y=7

y=7/-14

y=-1/2

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