-4(4y-3)+3y=3(y+2)

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Solution for -4(4y-3)+3y=3(y+2) equation: 



-4(4y-3)+3y=3(y+2)

We move all terms to the left:

-4(4y-3)+3y-(3(y+2))=0

We add all the numbers together, and all the variables

3y-4(4y-3)-(3(y+2))=0

We multiply parentheses

3y-16y-(3(y+2))+12=0



We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)



We add all the numbers together, and all the variables

-13y-(3y+6)+12=0

We get rid of parentheses

-13y-3y-6+12=0

We add all the numbers together, and all the variables

-16y+6=0

We move all terms containing y to the left, all other terms to the right

-16y=-6

y=-6/-16

y=3/8

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