-4(4y-3)-y=-3(y-5)

Solution for -4(4y-3)-y=-3(y-5) equation:

-4(4y-3)-y=-3(y-5)

We move all terms to the left:

-4(4y-3)-y-(-3(y-5))=0

We add all the numbers together, and all the variables

-1y-4(4y-3)-(-3(y-5))=0

We multiply parentheses

-1y-16y-(-3(y-5))+12=0


We calculate terms in parentheses: -(-3(y-5)), so:

-3(y-5)

We multiply parentheses

-3y+15

Back to the equation:

-(-3y+15)


We add all the numbers together, and all the variables

-17y-(-3y+15)+12=0

We get rid of parentheses

-17y+3y-15+12=0

We add all the numbers together, and all the variables

-14y-3=0

We move all terms containing y to the left, all other terms to the right

-14y=3

y=3/-14

y=-3/14