-4(4y-4)-y=-3(y-4)

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Solution for -4(4y-4)-y=-3(y-4) equation:



-4(4y-4)-y=-3(y-4)
We move all terms to the left:
-4(4y-4)-y-(-3(y-4))=0
We add all the numbers together, and all the variables
-1y-4(4y-4)-(-3(y-4))=0
We multiply parentheses
-1y-16y-(-3(y-4))+16=0
We calculate terms in parentheses: -(-3(y-4)), so:
-3(y-4)
We multiply parentheses
-3y+12
Back to the equation:
-(-3y+12)
We add all the numbers together, and all the variables
-17y-(-3y+12)+16=0
We get rid of parentheses
-17y+3y-12+16=0
We add all the numbers together, and all the variables
-14y+4=0
We move all terms containing y to the left, all other terms to the right
-14y=-4
y=-4/-14
y=2/7

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