-4(4y-8)-y=-2(y-5)

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Solution for -4(4y-8)-y=-2(y-5) equation: 



-4(4y-8)-y=-2(y-5)

We move all terms to the left:

-4(4y-8)-y-(-2(y-5))=0

We add all the numbers together, and all the variables

-1y-4(4y-8)-(-2(y-5))=0

We multiply parentheses

-1y-16y-(-2(y-5))+32=0



We calculate terms in parentheses: -(-2(y-5)), so:

-2(y-5)

We multiply parentheses

-2y+10

Back to the equation:

-(-2y+10)



We add all the numbers together, and all the variables

-17y-(-2y+10)+32=0

We get rid of parentheses

-17y+2y-10+32=0

We add all the numbers together, and all the variables

-15y+22=0

We move all terms containing y to the left, all other terms to the right

-15y=-22

y=-22/-15

y=1+7/15

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