-4(5-8b)=40+2b

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Solution for -4(5-8b)=40+2b equation: 



-4(5-8b)=40+2b

We move all terms to the left:

-4(5-8b)-(40+2b)=0

We add all the numbers together, and all the variables

-4(-8b+5)-(2b+40)=0

We multiply parentheses

32b-(2b+40)-20=0

We get rid of parentheses

32b-2b-40-20=0

We add all the numbers together, and all the variables

30b-60=0

We move all terms containing b to the left, all other terms to the right

30b=60

b=60/30

b=2

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