-4(5a-5)=2(4-10a)+12

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Solution for -4(5a-5)=2(4-10a)+12 equation:


Simplifying
-4(5a + -5) = 2(4 + -10a) + 12

Reorder the terms:
-4(-5 + 5a) = 2(4 + -10a) + 12
(-5 * -4 + 5a * -4) = 2(4 + -10a) + 12
(20 + -20a) = 2(4 + -10a) + 12
20 + -20a = (4 * 2 + -10a * 2) + 12
20 + -20a = (8 + -20a) + 12

Reorder the terms:
20 + -20a = 8 + 12 + -20a

Combine like terms: 8 + 12 = 20
20 + -20a = 20 + -20a

Add '-20' to each side of the equation.
20 + -20 + -20a = 20 + -20 + -20a

Combine like terms: 20 + -20 = 0
0 + -20a = 20 + -20 + -20a
-20a = 20 + -20 + -20a

Combine like terms: 20 + -20 = 0
-20a = 0 + -20a
-20a = -20a

Add '20a' to each side of the equation.
-20a + 20a = -20a + 20a

Combine like terms: -20a + 20a = 0
0 = -20a + 20a

Combine like terms: -20a + 20a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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