-4(5h-4)=2(10h+8)20h

Solution for -4(5h-4)=2(10h+8)20h equation:

-4(5h-4)=2(10h+8)20h

We move all terms to the left:

-4(5h-4)-(2(10h+8)20h)=0

We multiply parentheses

-20h-(2(10h+8)20h)+16=0


We calculate terms in parentheses: -(2(10h+8)20h), so:

2(10h+8)20h

We multiply parentheses

400h^2+320h

Back to the equation:

-(400h^2+320h)


We get rid of parentheses

-400h^2-20h-320h+16=0

We add all the numbers together, and all the variables

-400h^2-340h+16=0

a = -400; b = -340; c = +16;
Δ = b2-4ac
Δ = -3402-4·(-400)·16
Δ = 141200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{141200}=\sqrt{400*353}=\sqrt{400}*\sqrt{353}=20\sqrt{353}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-340)-20\sqrt{353}}{2*-400}=\frac{340-20\sqrt{353}}{-800}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-340)+20\sqrt{353}}{2*-400}=\frac{340+20\sqrt{353}}{-800}
$