-4(5x-3)=20x+12

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Solution for -4(5x-3)=20x+12 equation: 



-4(5x-3)=20x+12

We move all terms to the left:

-4(5x-3)-(20x+12)=0

We multiply parentheses

-20x-(20x+12)+12=0

We get rid of parentheses

-20x-20x-12+12=0

We add all the numbers together, and all the variables

-40x=0

x=0/-40

x=0

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