-4(5y+2)=2(6-10y)-20

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Solution for -4(5y+2)=2(6-10y)-20 equation:


Simplifying
-4(5y + 2) = 2(6 + -10y) + -20

Reorder the terms:
-4(2 + 5y) = 2(6 + -10y) + -20
(2 * -4 + 5y * -4) = 2(6 + -10y) + -20
(-8 + -20y) = 2(6 + -10y) + -20
-8 + -20y = (6 * 2 + -10y * 2) + -20
-8 + -20y = (12 + -20y) + -20

Reorder the terms:
-8 + -20y = 12 + -20 + -20y

Combine like terms: 12 + -20 = -8
-8 + -20y = -8 + -20y

Add '8' to each side of the equation.
-8 + 8 + -20y = -8 + 8 + -20y

Combine like terms: -8 + 8 = 0
0 + -20y = -8 + 8 + -20y
-20y = -8 + 8 + -20y

Combine like terms: -8 + 8 = 0
-20y = 0 + -20y
-20y = -20y

Add '20y' to each side of the equation.
-20y + 20y = -20y + 20y

Combine like terms: -20y + 20y = 0
0 = -20y + 20y

Combine like terms: -20y + 20y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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