-4(5y+5)-5y=7(y-2)-2

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Solution for -4(5y+5)-5y=7(y-2)-2 equation: 



-4(5y+5)-5y=7(y-2)-2

We move all terms to the left:

-4(5y+5)-5y-(7(y-2)-2)=0

We add all the numbers together, and all the variables

-5y-4(5y+5)-(7(y-2)-2)=0

We multiply parentheses

-5y-20y-(7(y-2)-2)-20=0



We calculate terms in parentheses: -(7(y-2)-2), so:

7(y-2)-2

We multiply parentheses

7y-14-2

We add all the numbers together, and all the variables

7y-16

Back to the equation:

-(7y-16)



We add all the numbers together, and all the variables

-25y-(7y-16)-20=0

We get rid of parentheses

-25y-7y+16-20=0

We add all the numbers together, and all the variables

-32y-4=0

We move all terms containing y to the left, all other terms to the right

-32y=4

y=4/-32

y=-1/8

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