-4(5y-10)=8+2(-10y+16)

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Solution for -4(5y-10)=8+2(-10y+16) equation:


Simplifying
-4(5y + -10) = 8 + 2(-10y + 16)

Reorder the terms:
-4(-10 + 5y) = 8 + 2(-10y + 16)
(-10 * -4 + 5y * -4) = 8 + 2(-10y + 16)
(40 + -20y) = 8 + 2(-10y + 16)

Reorder the terms:
40 + -20y = 8 + 2(16 + -10y)
40 + -20y = 8 + (16 * 2 + -10y * 2)
40 + -20y = 8 + (32 + -20y)

Combine like terms: 8 + 32 = 40
40 + -20y = 40 + -20y

Add '-40' to each side of the equation.
40 + -40 + -20y = 40 + -40 + -20y

Combine like terms: 40 + -40 = 0
0 + -20y = 40 + -40 + -20y
-20y = 40 + -40 + -20y

Combine like terms: 40 + -40 = 0
-20y = 0 + -20y
-20y = -20y

Add '20y' to each side of the equation.
-20y + 20y = -20y + 20y

Combine like terms: -20y + 20y = 0
0 = -20y + 20y

Combine like terms: -20y + 20y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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