-4(5y-2)+2y=-4(y+1)

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Solution for -4(5y-2)+2y=-4(y+1) equation: 



-4(5y-2)+2y=-4(y+1)

We move all terms to the left:

-4(5y-2)+2y-(-4(y+1))=0

We add all the numbers together, and all the variables

2y-4(5y-2)-(-4(y+1))=0

We multiply parentheses

2y-20y-(-4(y+1))+8=0



We calculate terms in parentheses: -(-4(y+1)), so:

-4(y+1)

We multiply parentheses

-4y-4

Back to the equation:

-(-4y-4)



We add all the numbers together, and all the variables

-18y-(-4y-4)+8=0

We get rid of parentheses

-18y+4y+4+8=0

We add all the numbers together, and all the variables

-14y+12=0

We move all terms containing y to the left, all other terms to the right

-14y=-12

y=-12/-14

y=6/7

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