-4(5y-4)+5y=3(y+2)

Solution for -4(5y-4)+5y=3(y+2) equation:

-4(5y-4)+5y=3(y+2)

We move all terms to the left:

-4(5y-4)+5y-(3(y+2))=0

We add all the numbers together, and all the variables

5y-4(5y-4)-(3(y+2))=0

We multiply parentheses

5y-20y-(3(y+2))+16=0


We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)


We add all the numbers together, and all the variables

-15y-(3y+6)+16=0

We get rid of parentheses

-15y-3y-6+16=0

We add all the numbers together, and all the variables

-18y+10=0

We move all terms containing y to the left, all other terms to the right

-18y=-10

y=-10/-18

y=5/9