-4(5y-5)-y=2(y-2)

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Solution for -4(5y-5)-y=2(y-2) equation:



-4(5y-5)-y=2(y-2)
We move all terms to the left:
-4(5y-5)-y-(2(y-2))=0
We add all the numbers together, and all the variables
-1y-4(5y-5)-(2(y-2))=0
We multiply parentheses
-1y-20y-(2(y-2))+20=0
We calculate terms in parentheses: -(2(y-2)), so:
2(y-2)
We multiply parentheses
2y-4
Back to the equation:
-(2y-4)
We add all the numbers together, and all the variables
-21y-(2y-4)+20=0
We get rid of parentheses
-21y-2y+4+20=0
We add all the numbers together, and all the variables
-23y+24=0
We move all terms containing y to the left, all other terms to the right
-23y=-24
y=-24/-23
y=1+1/23

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