-4(5y-5)-y=2(y-2)

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Solution for -4(5y-5)-y=2(y-2) equation: 



-4(5y-5)-y=2(y-2)

We move all terms to the left:

-4(5y-5)-y-(2(y-2))=0

We add all the numbers together, and all the variables

-1y-4(5y-5)-(2(y-2))=0

We multiply parentheses

-1y-20y-(2(y-2))+20=0



We calculate terms in parentheses: -(2(y-2)), so:

2(y-2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We add all the numbers together, and all the variables

-21y-(2y-4)+20=0

We get rid of parentheses

-21y-2y+4+20=0

We add all the numbers together, and all the variables

-23y+24=0

We move all terms containing y to the left, all other terms to the right

-23y=-24

y=-24/-23

y=1+1/23

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