-4(6x+2x+1x-2)=116

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Solution for -4(6x+2x+1x-2)=116 equation:



-4(6x+2x+1x-2)=116
We move all terms to the left:
-4(6x+2x+1x-2)-(116)=0
We add all the numbers together, and all the variables
-4(9x-2)-116=0
We multiply parentheses
-36x+8-116=0
We add all the numbers together, and all the variables
-36x-108=0
We move all terms containing x to the left, all other terms to the right
-36x=108
x=108/-36
x=-3

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