-4(6x-2)(x-1)=0

Solution for -4(6x-2)(x-1)=0 equation:

-4(6x-2)(x-1)=0

We multiply parentheses ..

-4(+6x^2-6x-2x+2)=0

We multiply parentheses

-24x^2+24x+8x-8=0

We add all the numbers together, and all the variables

-24x^2+32x-8=0

a = -24; b = 32; c = -8;
Δ = b2-4ac
Δ = 322-4·(-24)·(-8)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16}{2*-24}=\frac{-48}{-48}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16}{2*-24}=\frac{-16}{-48}
=1/3
$