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-4(6x-2)(x-1)=0
We multiply parentheses ..
-4(+6x^2-6x-2x+2)=0
We multiply parentheses
-24x^2+24x+8x-8=0
We add all the numbers together, and all the variables
-24x^2+32x-8=0
a = -24; b = 32; c = -8;
Δ = b2-4ac
Δ = 322-4·(-24)·(-8)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16}{2*-24}=\frac{-48}{-48} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16}{2*-24}=\frac{-16}{-48} =1/3 $
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