-4(6y-12)=-20y-20

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Solution for -4(6y-12)=-20y-20 equation: 



-4(6y-12)=-20y-20

We move all terms to the left:

-4(6y-12)-(-20y-20)=0

We multiply parentheses

-24y-(-20y-20)+48=0

We get rid of parentheses

-24y+20y+20+48=0

We add all the numbers together, and all the variables

-4y+68=0

We move all terms containing y to the left, all other terms to the right

-4y=-68

y=-68/-4

y=+17

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