-4(6y-2)-y=-3(y-2)

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Solution for -4(6y-2)-y=-3(y-2) equation: 



-4(6y-2)-y=-3(y-2)

We move all terms to the left:

-4(6y-2)-y-(-3(y-2))=0

We add all the numbers together, and all the variables

-1y-4(6y-2)-(-3(y-2))=0

We multiply parentheses

-1y-24y-(-3(y-2))+8=0



We calculate terms in parentheses: -(-3(y-2)), so:

-3(y-2)

We multiply parentheses

-3y+6

Back to the equation:

-(-3y+6)



We add all the numbers together, and all the variables

-25y-(-3y+6)+8=0

We get rid of parentheses

-25y+3y-6+8=0

We add all the numbers together, and all the variables

-22y+2=0

We move all terms containing y to the left, all other terms to the right

-22y=-2

y=-2/-22

y=1/11

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