-4(7z-)+5z=-2(3z+4)-3z

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Solution for -4(7z-)+5z=-2(3z+4)-3z equation: 



-4(7z-)+5z=-2(3z+4)-3z

We move all terms to the left:

-4(7z-)+5z-(-2(3z+4)-3z)=0

We add all the numbers together, and all the variables

-4(+7z)+5z-(-2(3z+4)-3z)=0

We add all the numbers together, and all the variables

5z-4(+7z)-(-2(3z+4)-3z)=0

We multiply parentheses

5z-28z-(-2(3z+4)-3z)=0



We calculate terms in parentheses: -(-2(3z+4)-3z), so:

-2(3z+4)-3z

We add all the numbers together, and all the variables

-3z-2(3z+4)

We multiply parentheses

-3z-6z-8

We add all the numbers together, and all the variables

-9z-8

Back to the equation:

-(-9z-8)



We add all the numbers together, and all the variables

-23z-(-9z-8)=0

We get rid of parentheses

-23z+9z+8=0

We add all the numbers together, and all the variables

-14z+8=0

We move all terms containing z to the left, all other terms to the right

-14z=-8

z=-8/-14

z=4/7

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