-4(7z-1)+5z=-2(3z+4)-32

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Solution for -4(7z-1)+5z=-2(3z+4)-32 equation: 



-4(7z-1)+5z=-2(3z+4)-32

We move all terms to the left:

-4(7z-1)+5z-(-2(3z+4)-32)=0

We add all the numbers together, and all the variables

5z-4(7z-1)-(-2(3z+4)-32)=0

We multiply parentheses

5z-28z-(-2(3z+4)-32)+4=0



We calculate terms in parentheses: -(-2(3z+4)-32), so:

-2(3z+4)-32

We multiply parentheses

-6z-8-32

We add all the numbers together, and all the variables

-6z-40

Back to the equation:

-(-6z-40)



We add all the numbers together, and all the variables

-23z-(-6z-40)+4=0

We get rid of parentheses

-23z+6z+40+4=0

We add all the numbers together, and all the variables

-17z+44=0

We move all terms containing z to the left, all other terms to the right

-17z=-44

z=-44/-17

z=2+10/17

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