-4(8-c)=(3c+7)

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Solution for -4(8-c)=(3c+7) equation: 



-4(8-c)=(3c+7)

We move all terms to the left:

-4(8-c)-((3c+7))=0

We add all the numbers together, and all the variables

-4(-1c+8)-((3c+7))=0

We multiply parentheses

4c-((3c+7))-32=0



We calculate terms in parentheses: -((3c+7)), so:

(3c+7)

We get rid of parentheses

3c+7

Back to the equation:

-(3c+7)



We get rid of parentheses

4c-3c-7-32=0

We add all the numbers together, and all the variables

c-39=0

We move all terms containing c to the left, all other terms to the right

c=39

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