-4(8-c)=-(3c+7)

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Solution for -4(8-c)=-(3c+7) equation: 



-4(8-c)=-(3c+7)

We move all terms to the left:

-4(8-c)-(-(3c+7))=0

We add all the numbers together, and all the variables

-4(-1c+8)-(-(3c+7))=0

We multiply parentheses

4c-(-(3c+7))-32=0



We calculate terms in parentheses: -(-(3c+7)), so:

-(3c+7)

We get rid of parentheses

-3c-7

Back to the equation:

-(-3c-7)



We get rid of parentheses

4c+3c+7-32=0

We add all the numbers together, and all the variables

7c-25=0

We move all terms containing c to the left, all other terms to the right

7c=25

c=25/7

c=3+4/7

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