-4(a-1)=5(4+3a)+3a

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Solution for -4(a-1)=5(4+3a)+3a equation:



-4(a-1)=5(4+3a)+3a
We move all terms to the left:
-4(a-1)-(5(4+3a)+3a)=0
We add all the numbers together, and all the variables
-4(a-1)-(5(3a+4)+3a)=0
We multiply parentheses
-4a-(5(3a+4)+3a)+4=0
We calculate terms in parentheses: -(5(3a+4)+3a), so:
5(3a+4)+3a
We add all the numbers together, and all the variables
3a+5(3a+4)
We multiply parentheses
3a+15a+20
We add all the numbers together, and all the variables
18a+20
Back to the equation:
-(18a+20)
We get rid of parentheses
-4a-18a-20+4=0
We add all the numbers together, and all the variables
-22a-16=0
We move all terms containing a to the left, all other terms to the right
-22a=16
a=16/-22
a=-8/11

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