-4(b+1)+2b=3(2b-)

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Solution for -4(b+1)+2b=3(2b-) equation: 



-4(b+1)+2b=3(2b-)

We move all terms to the left:

-4(b+1)+2b-(3(2b-))=0

We add all the numbers together, and all the variables

-4(b+1)+2b-(3(+2b))=0

We add all the numbers together, and all the variables

2b-4(b+1)-(3(+2b))=0

We multiply parentheses

2b-4b-(3(+2b))-4=0



We calculate terms in parentheses: -(3(+2b)), so:

3(+2b)

We multiply parentheses

6b

Back to the equation:

-(6b)



We add all the numbers together, and all the variables

-8b-4=0

We move all terms containing b to the left, all other terms to the right

-8b=4

b=4/-8

b=-1/2

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