-4(b+1)+2b=3(2b-1

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Solution for -4(b+1)+2b=3(2b-1 equation: 



-4(b+1)+2b=3(2b-1

We move all terms to the left:

-4(b+1)+2b-(3(2b-1)=0

We add all the numbers together, and all the variables

2b-4(b+1)-(3(2b-1)=0

We multiply parentheses

2b-4b-(3(2b-1)-4=0

We add all the numbers together, and all the variables

-2b-(3(2b-1)-4=0

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