-4(b+1)+2b=3(2b-2)

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Solution for -4(b+1)+2b=3(2b-2) equation: 



-4(b+1)+2b=3(2b-2)

We move all terms to the left:

-4(b+1)+2b-(3(2b-2))=0

We add all the numbers together, and all the variables

2b-4(b+1)-(3(2b-2))=0

We multiply parentheses

2b-4b-(3(2b-2))-4=0



We calculate terms in parentheses: -(3(2b-2)), so:

3(2b-2)

We multiply parentheses

6b-6

Back to the equation:

-(6b-6)



We add all the numbers together, and all the variables

-2b-(6b-6)-4=0

We get rid of parentheses

-2b-6b+6-4=0

We add all the numbers together, and all the variables

-8b+2=0

We move all terms containing b to the left, all other terms to the right

-8b=-2

b=-2/-8

b=1/4

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