-4(b+1)+2b=3(2b=3(2b-1)

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Solution for -4(b+1)+2b=3(2b=3(2b-1) equation:



-4(b+1)+2b=3(2b=3(2b-1)
We move all terms to the left:
-4(b+1)+2b-(3(2b)=0
We add all the numbers together, and all the variables
2b-4(b+1)-(32b=0
We multiply parentheses
2b-4b-(32b-4=0
We add all the numbers together, and all the variables
-2b-(32b-4=0

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