-4(b+1)+2b=3(2n-1)

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Solution for -4(b+1)+2b=3(2n-1) equation:


Simplifying
-4(b + 1) + 2b = 3(2n + -1)

Reorder the terms:
-4(1 + b) + 2b = 3(2n + -1)
(1 * -4 + b * -4) + 2b = 3(2n + -1)
(-4 + -4b) + 2b = 3(2n + -1)

Combine like terms: -4b + 2b = -2b
-4 + -2b = 3(2n + -1)

Reorder the terms:
-4 + -2b = 3(-1 + 2n)
-4 + -2b = (-1 * 3 + 2n * 3)
-4 + -2b = (-3 + 6n)

Solving
-4 + -2b = -3 + 6n

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + -2b = -3 + 4 + 6n

Combine like terms: -4 + 4 = 0
0 + -2b = -3 + 4 + 6n
-2b = -3 + 4 + 6n

Combine like terms: -3 + 4 = 1
-2b = 1 + 6n

Divide each side by '-2'.
b = -0.5 + -3n

Simplifying
b = -0.5 + -3n

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