-4(b+1)+2b=4(2b-1)

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Solution for -4(b+1)+2b=4(2b-1) equation: 



-4(b+1)+2b=4(2b-1)

We move all terms to the left:

-4(b+1)+2b-(4(2b-1))=0

We add all the numbers together, and all the variables

2b-4(b+1)-(4(2b-1))=0

We multiply parentheses

2b-4b-(4(2b-1))-4=0



We calculate terms in parentheses: -(4(2b-1)), so:

4(2b-1)

We multiply parentheses

8b-4

Back to the equation:

-(8b-4)



We add all the numbers together, and all the variables

-2b-(8b-4)-4=0

We get rid of parentheses

-2b-8b+4-4=0

We add all the numbers together, and all the variables

-10b=0

b=0/-10

b=0

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